Question

john makes $8 an hour walkin dogs and 16 an hour as a math tutor this weekend he wants to work no more than 10 hours he also wants to earn at least 96

Answer 1

This question can be solved using an Algebraic equation.

The system of equations is given as:

x + y ≤ 10

8x + 16y ≥ 96

Let's represent

x = number of hours he walks the dogs

y = number of hours he works as a maths tutor

John must work for no more than 8 hours walking the dog and 2 hours as a Maths tutor to earn at least $96.

Our system of equations is given as:

He wants to work no more than 10 hours.

No more is represented by the inequality "≤ " = Less than or equal to

x + y ≤ 10 ...........Equation 1

He also wants to earn at least 96.

At least is represented by the inequality" ≥" = Greater than or equal to

$8 × x + $16 × y  ≥ 96

8x + 16y ≥ 96........Equation 2

Solving for the number of hours

x + y = 10

x = 10 - y

Substitute 10 - y for x in Equation 2

8(10 - y) + 16y = 96

80 - 8y + 16y = 96

Collect like terms

8y = 96 - 80

8y = 16

Divide both sides by 8

8y/8 = 16/8

y = 2 hours

Solving for x

x = 10 - y

x = 10 - 2

x = 8 hours

Therefore, John must work for no more than 8 hours walking the dog and 2 hours as a Maths tutor to earn at least $96.

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