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AlladinOne [14]
2 years ago
15

Factor x3 – 4x2 7x – 28 by grouping. what is the resulting expression? (x2 – 4)(x 7) (x2 4)(x – 7) (x2 – 7)(x 4) (x2 7)(x – 4)

Mathematics
1 answer:
allochka39001 [22]2 years ago
5 0

An expression has numbers, variables, and mathematical operations. The factors of the expression x³-4x²+7x-28 are (x²+7)(x-4).

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The factors of the expression x³-4x²+7x-28 can be written as,

x^3-4x^2+7x-28\\

Take x² as the common factor from the first two terms while 7 as the common factor from the last two terms.

x^3-4x^2+7x-28\\\\=x^2(x-4)+7(x-4)\\\\=(x^2+7)(x-4)

Hence, the factors of the expression x³-4x²+7x-28 are (x²+7)(x-4).

Learn more about Expression:

brainly.com/question/13947055

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Answer:

The expression  Riley could have used to find the product of the two numbers is 24 × (30 + 7).

Step-by-step explanation:

The distribution property for multiplication is:

a\times (b+c)=a\cdot b+a\cdot c

In this case we need to determine the product of 37 and 24.

Compute the product as follows:

37\times 24=24\times (30 +7)

            =(24\times 30)+(24\times 7)\\=720+168\\=888

Thus, the product of 37 and 24 is 888.

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a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
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Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

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4 years ago
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