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3 years ago

What is −(−56) ? −65 56 65 I don't know.

Mathematics

1 answer:

Helen [10]3 years ago

6 0

Answer:

Step-by-step explanation:

-(-56) = -1 x -56 = 56

*Anytime you multiply two negatives the product/outcome will always be positive.

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The points (12, 23) and (14, 45) lie on a line. What is<br> the slope of the line?

ozzi

Answer:

slope= 11

Step-by-step explanation:

(12,23) = (x1,y1)

(14,45) = (x2,y2)

Now,

slope(m)= (y2-y1)/(x2-x1)

=(45-23)/(14-12)

=22/2

=11

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2 years ago

A rectangle has a height of 2y^3+5 and a width of y^3+6y.

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Answer:

in polynomial form

Step-by-step explanation:

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3 years ago

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Maddy and Caitlin spend a certain amount of money from their money box each month to buy bracelet-making supplies.

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Solutions

We know that <span>Function 1 shows a greater rate of change, because Maddy spends $20 each month and Caitlin spends $18.
</span>
Maddy spends 2 dollars more.

Therefore the correct answer is the last option.
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3 years ago

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How much greater is 747,784,936 than 373,892,468

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The answer is 373892468

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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of

prohojiy [21]

Answer:

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

Step-by-step explanation:

Information given

$\bar X¿ 17.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s¿4.2 represent the sample standard deviation

n¿65 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=65-1=64$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

8 0

3 years ago