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3 years ago

How would I do this?

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

8 0

we know that the shaded side is 90 degrees and we are given 28 degrees

So we add 90+28 and we get 118

Since a triangle has 180 degrees, we subtract 180-118 to fins the missing angle measure

180-118=62

x=62

Your equation is 180=90+28+x

gogolik [260]3 years ago

6 0

well it is a right triangle so you know the angle is 90

all angles in a triangle equal 180 degrees

so you make an equation

28+90+x=180

simplify

118+x=180

-118 -118

x=62 degrees

hope I was helpful

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A triangular prism. The rectangular sides are 3 feet by 2 feet, 3 feet by 2.5 feet, and 3 feet by 1.5 feet. The 2 triangular sid

Brrunno [24]

The amount of plywood that he needs to buy will be 21 square feet.

<h3>What is the surface area of the triangular prism?</h3>

Let the prism with a length of L of the rectangular surface.

And the dimension of the triangle is A, B, and C. Then we have

SA = 2(area of triangle) + 3(area of rectangle surface)

A triangular prism.

The rectangular sides are 3 feet by 2 feet, 3 feet by 2.5 feet, and 3 feet by 1.5 feet.

The 2 triangular sides have a base of 2 feet and a height of 1.5 feet.

Then the area of the triangle will be

⇒ 1/2 x 2 x 1.5

⇒ 1.5 square feet

The area of the rectangles will be

⇒ 3 x 2 + 3 x 2.5 + 3 x 1.5

⇒ 18 square feet

Then the surface area of the triangular prism will be

Surface area = 2 x 1.5 + 18

Surface arae = 3 + 18

Surface area = 21 square feet

More about the surface area of the triangular prism link is given below.

brainly.com/question/16765719

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7 0

2 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

In winter, the price of apples suddenly went up by$0.75 per pound. Sam bought 3 pounds of apples at the new price for a total of

White raven [17]

From the information given, the original price per pound was increased by $ 0.75
Let the original price be x, so the new price is x + 0.75

Sam bought 3 pounds of apples at new price and it cost him 5.88

so we form an equation:

3 (x + 0.75) = 5.88

3x + 2.25 = 5.88

3x = 5.88 - 2.25

3x = 3.63

x = 3.63 / 3

x = 1.21

Therefore the original price per pound is 1.21 dollars

4 0

3 years ago

Read 2 more answers

The charge for electricity consumption E is partly constant and partly varies as the number N of units used. The charge for 82 u

balandron [24]

The charge per unit of electricity is #415

The formula for E in terms of N is E = 375 + 40N

<h3>What is variation?</h3>

Variation is a mathematical term that establishes the relationship between quantities and variables in an equation.

Analysis:

E = K + CN

where K and C are constants

When E = 3655, N = 82 and when E = 2055, N = 42

3655 = K + 82C ---------------1

2055 = K + 42C----------------2

subtract equation 2 from 1

40C = 1600

C = 40

substitute C in equation 1

3655 = K + 82(40)

3655 = K + 3280

K = 3655 - 3280 = 375

charge per unit is N = 1

E = 375 + 40(1) = #415

Formula for E in terms of N is E = 375 + 40N

In conclusion, the charge per unit of electricity is 415 and the equation connecting E and N is E = 375 + 40N

Learn more about Variation: brainly.com/question/6499629

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3 0

2 years ago

What is 4x=8 thanks ;)

Reika [66]

Answer:

x=2

Step-by-step explanation:

4x=8

4x/4= 8/4 Divide both side by four to find x

8/4= 2 which equals x

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3 years ago

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