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Darina [25.2K]
2 years ago
5

Math assignment please help me with this question

Mathematics
1 answer:
nalin [4]2 years ago
4 0

Answer:

<h2>sorry hindi KO po alam sorry po talaga</h2>
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What is the answer to 4|x-1|=12
STatiana [176]

Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12             Divide by 4

  • abs(x - 1) = 12/4            
  • abs(x - 1) = 3                  Equate this to 3
  • x - 1 = 3                          Add 1 to both sides
  • x - 1 + 1 = 3 + 1               Combine
  • x = 4

4*abs(x - 1) = - 12         Divide by 4

  • abs(x - 1) = - 12/4
  • abs(x - 1) = - 3
  • x - 1 = - 3                       Add 1 to both sides
  • x - 1 + 1 = -3 + 1
  • x = - 2

So this has 2 answers

(4,0) and (- 2,0)

5 0
2 years ago
Four times as many apples. Algebraic expression
Leno4ka [110]
4x. hope that helped
8 0
3 years ago
Determine whether the function is linear (0,1) (-2,-1) (-4,1)
Brut [27]

Answer:

No, this is not a linear function

Step-by-step explanation:

If you graph each point, you will notice that none of the three points line up together in one line with a consitstant slope.

6 0
2 years ago
What is the equation of the line that is perpendicular to the graph of x=48-4y
8090 [49]

Answer:

find y intercept: x= 0 => y = 12

y = -x + 12 (1)

y = x + 12 (2) is answer

Step-by-step explanation:

8 0
3 years ago
Find all solutions to the equation.<br><br> 7 sin2x - 14 sin x + 2 = -5
cestrela7 [59]

\bf 7sin^2(x)-14sin(x)+2=-5\implies 7sin^2(x)-14sin(x)+7=0 \\\\\\ \stackrel{\textit{notice, this is just }ax^2+bx+c}{\stackrel{\stackrel{ax^2}{\downarrow }}{sin^2(x)}\stackrel{\stackrel{bx}{\downarrow }}{-2sin(x)}\stackrel{\stackrel{c}{\downarrow }}{+1}}=0\implies [sin(x)-1][sin(x)-1]=0 \\\\\\ sin(x)-1=0\implies sin(x)=1\implies \measuredangle x=sin^{-1}(1)\implies \measuredangle x=\cfrac{\pi }{2} \\\\\\ ~~~~~~~~~~~~~~\stackrel{\textit{and for all solutions using }n \in \mathbb{Z}}{\cfrac{\pi }{2}+2\pi n}

7 0
3 years ago
Read 2 more answers
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