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ikadub [295]
3 years ago
14

Elaine opens a checking account with a deposit of $20.00 and wants to put the same amount of money

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0

Answer: 200 = m x 10 + 20

Step-by-step explanation:

She wants a balance of 200 with the same amount of money (m) going into the account for 10 weeks plus the amount she began with

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Find the value of |-4| - 5 · 2(-1 + 3).
vredina [299]

Use PEMDAS

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and |a| = a for a ≥ 0 or |a| = -a for a < 0.

|-4| - 5 · 2(-1 + 3) =-(-4) - 5 · 2(2) = 4 - 10(2) = 4 - 20 = -16

6 0
3 years ago
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What's the circumference of a
grandymaker [24]

Answer:

56.55 inches

Step-by-step explanation:

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To stay in a hotel it costs $104 each night (n) plus a $15 fee for parking. Think of the linear function that demonstrates the t
Anna007 [38]

Answer:

the equation is:    (104 * x) + 15 = y     i believe

Step-by-step explanation:

104 OF THE NUMBER of nights so times x because you dont know the number

and + 15 because of the fee

7 0
3 years ago
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Answer:

A= 1/2(2x)(x+7)

Step-by-step explanation:

4 0
3 years ago
Mary wants to hang a mirror in her room. The mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and
Umnica [9.8K]

Answer:

The quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.

Now to calculate the length and width of the frame consider following calculation,

Width of frame HG = x + DC + x  

Width of frame HG = x + 2 + x  

Width of frame HG =  2 + 2x  

2x is the addition of the thickness which is present on both side of mirror

Length of frame FG = x + BC + x

Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

Since it is an rectangular frame, so using the formula for area of rectangle

Area\:of\:rectangle = length \times width

Given that area of frame is 7\:ft^{2}

Substituting the value,

7 = \left(3+2x\right)\times \left(2+2x\right)

Therefore, the quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

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3 years ago
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