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svet-max [94.6K]
3 years ago
12

WILL MARK YOU BRAINLESTA games shop sells marbles

Mathematics
1 answer:
Otrada [13]3 years ago
5 0
The answer is

The diameter is 4 (2) = 8 and height is 10(2) = 20

For the sides, use area of a cylinder = ph

p = 8 pi cm, ht = 20 cm. A = 160 pi sq cm

Base are 2 circles, each with radius 4 pi

Area = pi r^2 = 16 pi (times 2 circles) = 32 pi sq cm
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Ava is making punch for the entire class. She mixed 3 gallons of lemonade with every 7 gallons of Hawaiian Fruit Punch to make t
irina [24]

Answer:

3:7

Step-by-step explanation:

3 parts of lemonade to 7 parts punch

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2 years ago
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Number 1 has a picture
MA_775_DIABLO [31]
Question 1

cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17

Answer: Choice C) 15/17

=============================================

Question 2

sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25

So angle E is the answer

=============================================

Question 3

AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse

cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7

Answer: 11.7

=============================================

Question 4

x = length of board

cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5

Answer: 10.5

=============================================

Question 5

112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg

tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6

Answer: 210.6
3 0
3 years ago
To calculate the area of a circle, you may use a formula. True False
Whitepunk [10]

Answer:

True

Step-by-step explanation:

The formula for an area of a circle is a = pi times radius squared

5 0
3 years ago
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Need help with angles need it today
givi [52]
ANSWER: adjacent angles
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3 years ago
Calculate a vector c in the same direction of the vector a and that has the same length as the vector b
Viktor [21]

For any scalar t>0, t\vec a is a vector pointing in the same direction as a.

To force this vector to have the same length as another vector \vec b, first normalize t\vec a by dividing it by its norm,

\dfrac{t\vec a}{\|t\vec a\|}=\dfrac{t\vec a}{t\|\vec a\|}=\dfrac{\vec a}{\|\vec a\|}

then multiply this vector by the norm of \vec b, so that

\vec c=\dfrac{\|\vec b\|}{\|\vec a\|}\vec a

To confirm that \vec c has the same length as \vec b:

\|\vec c\|=\left\|\dfrac{\|\vec b\|}{\|\vec a\|}\vec a\right\|=\dfrac{\|\vec b\|}{\|\vec a\|}\|\vec a\|=\|\vec b\|

8 0
3 years ago
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