Answer:
Step-by-step explanation:
A. 1200(1.078)⁵ = 1746.928179
B. 1200(1+.072*5)= 1632
Option A
<h3>
Answer: 3 bottles of brand A</h3>
Explanation:
The pricing/cost information is not used in this problem. All we care about is the number of bottles, and how much each bottle can hold.
Brand A bottles hold 0.95 liters each. We bought 3 of these bottles, so 3*0.95 = 2.85 liters in total are purchased.
Brand B bottles hold 0.55 liters each. Buying 5 of them leads to 5*0.55 = 2.75 liters in total.
Going with the brand A option leads to more juice by 0.10 liters (subtract 2.85 and 2.75)
(a).
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
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(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .