Answer:
Step-by-step explanation:
<u>Sides are:</u>
<u>There are following number of posts on each of the sides:</u>
- 20 ft side ⇒ 20/5 = 4
- 25 ft side ⇒ 25/5 = 5
- 35 ft side ⇒ 35/5 = 7
<u>Total number:</u>
The new mean age will be greater than 14.2 years because the teacher is older than the previous mean.
The first one is your answer because if you plug into the cal it shows the x and y table and it shows that the first one is correct.
\left[x \right] = \left[ 6\right][x]=[6] totally answer
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
