Answer:
m∠BOC is 2.182 radian.
Step-by-step explanation:
Given,
Points B and C lie on the circle that having the radius 5 units and center O,
Such that, Arc BC = 10.91 units,
We know that,
The arc length is,
![S=r\times \theta](https://tex.z-dn.net/?f=S%3Dr%5Ctimes%20%5Ctheta)
Where, r is the radius and
( in radians ) is the central angle made by the arc,
Here, r = 5 units, S = 10.91 units,
By substituting the values,
![10.91=5\times \theta](https://tex.z-dn.net/?f=10.91%3D5%5Ctimes%20%5Ctheta)
![\implies \theta = \frac{10.91}{5}=2.182\text{ radian}](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctheta%20%3D%20%5Cfrac%7B10.91%7D%7B5%7D%3D2.182%5Ctext%7B%20radian%7D)
Hence, m∠BOC = 2.182 radian.