Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
Answer:
So the statement:
"The product of two irrational numbers is rational." is false.
Step-by-step explanation:
The product of two irrationals can be irrational or rational.
Example:
is irrational but when you multiply it to itself the output is rational.
Example:
are irrational and when you multiply them you get an irrational answer of
.
So the statement:
"The product of two irrational numbers is rational." is false.
For this case we have the following variable:
p: cost of the item that Arthur wants to buy before tax
The expression for the 6% tax is given by:
Or equivalently:
Therefore, two different expressions for the total cost are:
Expression 1:
Expression 2:
To prove that they are equal, suppose that the item costs $ 100:
Expression 1:
Expression 2:
Since the cost is the same, then the expressions are the same.
Answer:
Two different expressions that model the problem are: