A bowl has 3 red beads and 7 blue beads. Two beads are selected at random one at a time. First a red bead is drawn and placed on

Question

1 year ago

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a table. Next a blue bead is drawn.
What is the probability of this event?

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1 answer:

IceJOKER [234] · Answer 1 · 2023-06-29T13:06:12+03:00

The probability that first a red bead is drawn and next a blue bead is drawn is 7/30,and both events are dependent

<h3>How to determine the probability?</h3>

The distribution of the beads are:

Red = 3

Blue = 7

Total = 10

The probability of selecting the red bead first is:

P(Red) = 3/10

When the red bead is selected, the number of beads becomes 9

So, the probability of selecting a blue bead is

P(Blue) = 7/9

The probability of the event is then calculated using:

P = 3/10 * 7/9

Evaluate

P = 7/30

Hence, the probability of the event is 7/30