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The volume of HCl gas required to prepare the solution is 101.54 L
<h3>How to determine the mole of HCl </h3>
- Volume of solution = 1.25 L
- Molarity = 3.20 M
- Mole of HCl =?
Mole = Molarity x Volume
Mole of HCl = 3.2 × 1.25
Mole of HCl = 4 moles
<h3>How to determine the volume of HCl </h3>
- Number of mole (n) = 4 moles
- Temperature (T) = 30 °C = 30 + 273 = 303 K
- Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:
PV = nRT
Divide both side by P
V = nRT / P
V = (4 × 0.0821 × 303) / 0.98
V = 101.54 L
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Answer:
i think it's f(x)=0. 2(0.2x)
hope this helps
