Question

HELP

Answer 1

I believe the answer is the ship is traveling at 21.25 MPH, started 10.5 miles from lighthouse and after 11 hours will be 244.25 miles from the lighthouse.

Answer 2

Answer:

Ques 1)

After 11 hours, the cruise ship will be 244.25 nautical miles from the lighthouse.

Ques 2)

At the start of the journey, the cruise ship was 10.5 nautical miles from the lighthouse.

Ques 3)

The cruise ship is traveling at a speed of 21.25 nautical miles per hour.

Step-by-step explanation:

We are given a table that represents the number of hours and distance from the Lighthouse as:

Time (in hours)              Distance from Lighthouse

                                       (nautical miles)

       2                                   53

       4                                  95.5

       6                                   138

       10                                   223

       12                                 265.5

As the speed is uniform hence, we can find the equation that represents the distance in term of the number of hours.

( As the speed is uniform hence, we get a constant slope i.e. we get a equation of a line)

As we know that the equation of a line passing through two points (a,b) and (c,d) is given by:

$y-b=\dfrac{d-b}{b-a}\times (x-a)$

Let (a,b)=(2,53) and (c,d)=(4,95.5)

where y denote the distance from lighthouse and x denotes the number of hours.

Hence, the equation of line is:

$y-53=\dfrac{95.5-53}{4-2}\times (x-2)\\\\\\y-53=21.25(x-2)\\\\y-53=21.25x-42.5\\\\y=21.25-42.5+53\\\\y=21.25x+10.5$

• Now when x=11 we have:

$y=21.25\times 11+10.5\\\\\\y=244.25$

Hence,

After 11 hours, the cruise ship will be 244.25 nautical miles from the lighthouse.

• Now when x=0 we have:

$y=21.25\times 0+10.5\\\\\\y=10.5$

Hence,

At the start of the journey, the cruise ship was 10.5 nautical miles from the lighthouse.

• Now the speed of the cruise ship is equal to the slope of the equation.

We have slope=21.25

Hence,

The cruise ship is traveling at a speed of 21.25 nautical miles per hour.