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The area of a rectangle is length times width
Answer:
60
Step-by-step explanation:
You need to think of it as an equation system.
First of all, let's call A the apple trees, P the pear trees and V the avocado's trees.
As for every 3 pear trees we have 4 apple trees, it can be written as:
4A = 3P
Then, we can clear the pears dividing both sides by 3:
4A/3 = 3P/3
(4/3)A = P
This is, we have one pear tree for every 4/3 apple trees.
Then we go to the other relation. For every 5 pears trees there are two avocados trees:
2V = 5P
As we want the ratio of avocados to apples we can replace the pear trees by it's expression depending on A:
2V = 5 ((4/3)A)
2V = (20/3) A
Multiplying both sides by 9 we make appear our 18 avocados trees:
2V *9 =( 20/3) A * 9
18 V = 60 A
So, for 18 avocados trees we have 60 apple trees.
Answer: The volume of the stone is 576 cubic inches
Step-by-step explanation: The dimensions of the tank are given in feet and inches, hence we shall use the lower of the unit of measurement that is, inches. Note that 1 foot equals 12 inches, so the length is 2 feet times 12, which equals 24 inches. Also the width is 1 foot times 12 which equals 12 inches. Then the tank is filled with water up to a depth of 8 inches , so the volume of water in the tank can be calculated as follows;
Volume = L x B x H
Where Length = 24, Width = 12 and Height = 8
Volume = 24 x 12 x 8
Volume = 2304
At 2304 cubic inches, a stone is placed in the water tank and the water level rises by 2 inches which implies that the depth is now 10 inches. With the addition of the stone, the dimensions are now shown as;
Length = 24, Width = 12, and Height = 10
Volume = L x W x H
Volume = 24 x 12 x 10
Volume = 2880
With the rise in volume of water in the tank, the difference (which is the volume of the stone) now is Volume with stone minus volume without stone, that is
Volume of stone = 2880 - 2304
Volume of stone = 576
Therefore the volume of the stone is 576 cubic inches
51 + 30 + 69 = 150 total
probability purchased grape flavor = 30/150 = 0.2
answer
A. 0.2
