Answer:
a. mixotrophs
b. autotrophs
c. syntrophs
d. phototrophs
e. heterotrophs
f. chemolithotrophs
g. chemotrophs
Explanation:
Autotrophs are organisms that can synthesize their own food using carbon dioxide (CO2) and water (e.g., algae, cyanobacteria, plants, etc). Syntrophs are organisms that utilize products from other organisms (e.g., mites that consume human dead-skin). Phototrophs are organisms that synthesize their own food by using the energy provided by sunlight (e.g., green plants). Heterotrophs are organisms that cannot synthesize their own food, obtaining energy and nutrients by consuming other organisms (e.g., animals). Mixotrophs are flexible organisms that obtain their food by using a mix of different sources of energy and carbon. Protists that combine autotrophy and heterotrophy are considered mixotrophs. Chemotrophs are organisms that obtain energy by the oxidation of electron donors from the environment, by using both organic sources (chemoorganotrophs) and inorganic sources (chemolithotrophs). Examples of chemolithotrophs include sulfur/iron-oxidizing bacteria, while chemoorganotrophs include the most known bacteria and archaea.
Answer:
The Protein would be made of the wrong amino acids
Explanation:
Pepsin (D.)
Pepsin is an enzyme that break down protein to make smaller peptide, in other words, they break up polypeptidae into peptide.
Hope it helped,
BioTeacher101
<u>Answer:</u>
<em>
heat is released by the combustion of 
of methane</em>
<u>Explanation:</u>
The value of enthalpy determines whether the reaction is exothermic or endothermic. If the enthalpy change is positive, then the reaction is endothermic (heat or energy released) and if the enthalpy change is negative then the reaction is exothermic (heat or energy absorbed).
![\Delta H \ reaction=[ 2(\Delta HfCO_2)+ 4(\Delta HfH_2O)]-[2(\Delta HfCH_4)+4(\Delta HfO_2)]](https://tex.z-dn.net/?f=%5CDelta%20H%20%5C%20reaction%3D%5B%202%28%5CDelta%20HfCO_2%29%2B%204%28%5CDelta%20HfH_2O%29%5D-%5B2%28%5CDelta%20HfCH_4%29%2B4%28%5CDelta%20HfO_2%29%5D)
=![2 ( -(393.5 KJ)/mol)-[2( -74.6 KJ/mol)+4(-241.82 KJ/mol)]](https://tex.z-dn.net/?f=2%20%28%20-%28393.5%20KJ%29%2Fmol%29-%5B2%28%20-74.6%20KJ%2Fmol%29%2B4%28-241.82%20KJ%2Fmol%29%5D)
![= -787 KJ/mol-[ -149.2 KJ/mol-967.28 KJ/mol]](https://tex.z-dn.net/?f=%3D%20-787%20KJ%2Fmol-%5B%20-149.2%20KJ%2Fmol-967.28%20KJ%2Fmol%5D)
<em>In this question, </em><em>the enthalpy of formation</em><em> has positive value and hence the </em><em>reaction is endothermic</em><em> in which the heat is released.
</em>
Answer:
Hello. You did not enter the answer options, but the factor that most directly influences a measurable result in an experiment is the manipulation of the variables.
Explanation:
In an experiment, the manipulation of variables becomes highly important so that it is possible to measure, that is, evaluate the result. This is because it is the variables that express values that represent the characteristics that are being analyzed and studied within the experiment. Therefore, the manipulation between them must be done in a very rational and balanced way so as not to modify the values shown by them, changing the data and generating false or immeasurable data.
