In this problem, you are looking at a pair of similar trapezoids. So we must be looking for a ratio between a side in the smaller trapezoid and the corresponding side in the bigger trapezoid. We are given the lengths of AB and EF, which we can use to find this ratio.
But before we do anything we must convert units so that all units are the same. Let's convert the 60 feet into inches. 60 feet is 720 inches.
Next, set up the ratio I mentioned earlier. If we set up the ratio so that it is smaller:larger, we would get 4:720, which simplifies to 1:180. Basically what this ratio says is that every 1 inch in the smaller trapezoid corresponds to 180 inches in the bigger trapezoid. Now we can use this ratio to find the lengths of the sides in the bigger trapezoid. Just multiply all the lengths of the smaller trapezoid by 180 to get the lengths for the bigger trapezoid. Finally, when we have all our side lengths, divide them all by 12 (because 12 inches in 1 foot) to get the measurements in feet.
From here, I'll let you find the total length yourself.
Answer:
21
Step-by-step explanation:
you first look at the circle
next you see the numbers in the circle
after that you multiply the numbers together
so, 3 x 7 = 21
It's easy it's just 62×9 it equals 558
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.
640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each
2AC = CF = 2FK
2(160) = 320 = 2(160)
BG = 20 m
20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x
Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
Answer:
F , D, A
Step-by-step explanation:
As we know vertical stretch of f(x) happens when we chane the value of the patameter a in this general form:
y = a. f(k(x-d))+ c
when |a| > 1 because When |a| > 1 (when a is greater than 1), the function is stretched vertically by a dilation factor of |a|.
So we choose, F , D, A
