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nignag [31]
3 years ago
6

Instructions: Write an expression to represent the given scenario.

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

60-5t=45

Step-by-step explanation:

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If using the method of completing the square to solve the quadratic equation
Softa [21]

Answer:

The number that would be added to make x^2-19x-3=0 a complete square is \mathbf{(\frac{19}{2})^2}

Step-by-step explanation:

We need to solve the expression x^2-19x-3=0 using completing the square method.

Completing square method is of form: (a-b)^2=a^2-2ab+b^2

We need to find the term, that it a complete square

The middle term is -19x so, it can be made as: -2(x)(19/2) according to the formula a^2-2ab+b^2

We have a=x and b=19/2

So, adding and subtracting (19/2)^2

x^2-2(x)(\frac{19}{2} )+(\frac{19}{2})^2- (\frac{19}{2})^2-3=0\\(x-\frac{19}{2})^2-\frac{361}{4}-3=0\\

So, the number that would be added to make x^2-19x-3=0 a complete square is \mathbf{(\frac{19}{2})^2}

6 0
3 years ago
Solve by factoring or finding square roots. -4x^2+3x = -1
zloy xaker [14]

Answer: (x+\frac{1}{4})(x-1)=0\\x_1=-\frac{1}{4}\\x_2=1

Step-by-step explanation:

1. To solve this problem the first thing you can do is divide both sides of the quadractic equation by -4, then:

x^{2}-\frac{3}{4}x+\frac{1}{4}=0

2. Now, to factor the quadratic equation you must find two numbers whose sum is -3/4 and the product is 1/4. These numbers are -1/4 and 1. Therefore, you have:

(x+\frac{1}{4})(x-1)=0

3. And the roots are:

 x_1=-\frac{1}{4}\\x_2=1

6 0
4 years ago
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What is the area, in square inches, of a circle with a diameter equal to 16 inches?
Lostsunrise [7]

Answer: 201.06 in²

Step-by-step explanation:

Use the equation πr² to find out the area of a circle.

Since the diameter is 16 the radius is half of that, 8.

π(8)²

Work out that equation and you're done!

7 0
3 years ago
WILL GIVE THE BRAIN THING
antiseptic1488 [7]

Not in domain

in domain

not in domain

5 0
3 years ago
What is an equivalent fraction for 8/9
svetoff [14.1K]
16/18
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6 0
4 years ago
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