Answer:
The genotype of male with red-green color blindness is XY, X chromosome possessing recessive allele of gene responsible for differentiating red-green color.
Explanation:
Color blindness is sex-linked trait and its inheritance follows criss-cross pattern. Dominant gene of allelomorpihc pair enables a person to differentiate between red and green color.
The genotype of male and female are different for the pair of sex chromosomes. Male is hetero-zygous (XY) and female is homo-zygous (XX). The gene controlling this trait is present on X chromosome.
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Answer:
The main function of the virion is to deliver its DNA or RNA genome into the host cell so that the genome can be expressed (transcribed and translated) by the host cell. The viral genome, often with associated basic proteins, is packaged inside a symmetric protein capsid.
Explanation:
what is a virus A virus is a submicroscopic infectious agent that replicates only inside the living cells of an organism. Viruses infect all life forms, from animals and plants to microorganisms, including bacteria and archaea. Since Dmitri Ivanovsky's 1892 article describing a non-bacterial pathogen infecting tobacco plants and the discovery of the tobacco mosaic virus by Martinus Beijerinck in 1898, more than 9,000 virus species have been described in detail of the millions of types of viruses in the environment. Viruses are found in almost every ecosystem on Earth and are the most numerous type of biological entity. The study of viruses is known as virology, a subspeciality of microbiology.
Answer:
Translation
Explanation:
The translation is the process during which the nucleotide sequence of the mRNA is read in the form of genetic codes. The nucleotide sequence of mRNA is complementary to the template DNA strand. According to the sequence of the nucleotides in the mRNA, the amino acids are added in a specific order to make the polypeptide chains. The process occurs on ribosomes. The ribosomes move along the mRNA to read its sequence and the tRNA brings are amino acids to be added to the polypeptide chains.
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
