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gayaneshka [121]
3 years ago
7

Classify the number −25.

Mathematics
2 answers:
Valentin [98]3 years ago
6 0
Answer:
Rational, integers, and real numbers


Andreyy893 years ago
4 0

Answer: a negative integer, rational number, and real number

Step-by-step explanation:

I don’t know exactly what you’re asking but here you go

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For a sparkling apple juice recipe with two ingredients, Timmy uses 3 1/4 cups of apple juice and 4 2/3 cups of lemon-lime soda.
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Answer:

anlamiyorum ne diyorsun

4 0
3 years ago
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Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


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3 years ago
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What is the highest common factor of 1,296 and 960???????????
kenny6666 [7]
The highest common factor is 48.
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3 years ago
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Y+9-x; use x=1, and y=3
borishaifa [10]

Answer:

13

Step-by-step explanation:

because 3+9=12+1=13

7 0
3 years ago
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Examine the pattern in the powers of i you wrote in the table, and create a rule for finding the value of large powers of i. Jus
denpristay [2]
Let N be any integer. Then

i^N=\begin{cases}1&\text{if }N\equiv0\mod4\\i&\text{if }N\equiv1\mod4\\-1&\text{if }N\equiv2\mod4\\-i&\text{if }N\equiv3\mod4\end{cases}

In other words:

(1) If N is a multiple of 4, then i^N=1.

(2) If dividing N by 4 leaves a remainder of 1, then i^N=i, since i^N=i^{4n+1} for some integer n, and from (1) we know that i^{4n+1}=i^{4n}i=i (because, obviously, 4n is a multiple of 4).

(3) If instead you get a remainder of 2, then i^N=-1. This follows from (1) as well. i^N=i^{4n+2}=i^{4n}i^2=(1)(-1)=-1.

(4) Finally, if you get a remainder of 3, then i^N=i^{4n+3}=i^{4n}i^2i=(1)(-1)(i)=-i.
5 0
3 years ago
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