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Sauron [17]
2 years ago
14

Is -5 a solution to the equation 6x+5=5x+8+2x? explain

Mathematics
1 answer:
boyakko [2]2 years ago
3 0

Answer:

no

Step-by-step explanation:

6x-5x-2x=8-5

-1x=3

-1x/-1=3/-1

x=-3

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If the revenue for the week is $2000, and labor consists of two workers earning $8.00 per hourwho worked 40 each, what is labor
julsineya [31]
Labor costs of the workers at $8 per hour working 40 hours each=$640
Revenue for the week=$2000
therefore labor cost as a percentage of revenue would be=32%
8 0
3 years ago
2. What helps you to get the root of a number?​
xeze [42]

Answer:

Separate The Digits Into Pairs.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
Solve each of the following equations. (2 answers)<br><br> |2x-3|=2
Roman55 [17]

Answer:

x= 5/2 or 1/2

Step-by-step explanation:

absolute value always gives us positive

if |u| = 2, u can be -2 or 2

2x-3 = 2

2x = 5

x = 5/2

2x-3 = -2

2x = 1

x= 1/2

in general, set the stuff inside the absolute value to equal both positive and negative of the equivalent value

6 0
2 years ago
The product of three and a squared number is twice the sum of the number and four
Setler [38]
3x^2 = 2(x + 4)
3x^2 = 2x + 8
3x^2 - 2x - 8 = 0
(3x + 4)(x - 2) = 0

3x + 4 = 0
3x = -4
x = -4/3

x - 2 = 0
x = 2

solution is : x = -4/3 or x = 2 <==
3 0
3 years ago
Read 2 more answers
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