<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Answer:
Graph has been shown in the attached file.
Step-by-step explanation:
We have been given the system of equations

Both the equation represents a straight lines. We can find the x and y intercepts of these lines to graph.
The intercept form of a line is given by

Here a is the x - intercept and b is the y-intercept.
Divide both sides of the equation (1) by 16

Hence, x-intercept = 4 and the point is (4,0)
y-intercept = 4 and the point is (0,4)
Similarly, for the second line
Divide both sides of the equation (2) by -6

x-intercept = -6 and the point is (-6,0)
y-intercept = -1 and the point is (0,-1)
We'll plot these points in the xy- plane and then join to get the graph of these lines.
What’s the question? I just see dots
Answer:
D(–5,3) and E(–5,1)
Step-by-step explanation:
i just took the test!
(X-(-2))2+(y-5)2=10
Is the third