Answer:
93.6 ml
Step-by-step explanation:
12% of that 780 ml is pure acid: 0.12(780 ml) = 93.6 ml
216
...................................
Answer:
10 cm
Step-by-step explanation:
The volume of a sphere is given by the formula ...
V = 4/3πr³
The volume of a cone is given by the formula ...
V = 1/3πr²h
The ratio of the volume of the cone to that of the sphere is ...
Vcone/Vsphere = (1/3πr²h)/(4/3πr³) = h/(4r)
In order for the ratio to have a value of 1, we must have ...
h = 4r
The height of the cone must be 4×2.5 cm = 10 cm to fit all of the ice cream.
A)


b)
since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP
thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)
c)
what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

Answer:
In this problem, we are given the following functions:

and its inverse function:

First of all, we want to calculate
. This can be obtained by substituting
x = 2
into f(x). Doing so, we find:

Then we want to calculate
. We can do it by substituting
x = 1
into
. Doing so,

Then we want to calculate
, which can be found by calculating f(2) and then using it as input for
We know that
f(2) = 1
Therefore,

Then we want to calculate
, which can be calculated by plugging
x = -2
into
. Doing so,

Then we want to calculate
; by substituting
x = 4
into f(x), we find

Finally, we want to find 
We know already that

So we have:
