All categories

3 years ago

Solve 25 = 5x − 4. one half 2 4 6

Mathematics

1 answer:

swat323 years ago

3 0

Answer:

29/5 =x

Step-by-step explanation:

25 = 5x − 4

Add 4 to each side

25+4 = 5x − 4+4

29 = 5x

Divide each side by 5

29/5 = 5x/5

29/5 =x

You might be interested in

Diana received 65 points on a project for school. She can make changes and receive three-tenths of the missing points back.She c

WITCHER [35]

65 out of 100 = 25
25/3 = 7.5
7.5 * 10

6 0

4 years ago

What is 10÷5/8 in a math order.

Sedbober [7]

If you would like to calculate <span>10÷5/8, you can do this using the following steps:

</span><span>10÷5/8 = (10/5)/8 = 2/8 = 1/4 = 0.25

The correct result would be 1/4 or 0.25.</span>

3 0

4 years ago

Write a number that rounds to 20,000 when its rounded to the nearest ten thousand?

laiz [17]

19,999 because 5 and up round it up, lower than 5 round it down.

4 0

3 years ago

Will give brainliest The surface area of the triangular prism is

meriva

yes the answer is on g00gle

Step-by-step explanation:

5 0

3 years ago

Suppose that you want to estimate the mean pH of rainfalls in an area that suffers from heavy pollution due to the discharge of

labwork [276]

Answer:

The number of rainfalls is $n =96$

The answer to the second question is no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid.

Step-by-step explanation:

from the question we are told that

The standard deviation is $\sigma = 0.5$

The margin of error is $E = 0.1$

Given that the confidence level is 95% then we can evaluate the level of significance as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we will obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the value is $Z_{\frac{\alpha }{2} } = 1.96$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} * \sigma }}{ E} ]^2$

substituting values

$n = [\frac{1.96 * 0.5 }{ 0.1} ]^2$

$n =96$

The answer to the second question is no the validity is null this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid

5 0

4 years ago