well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Answer:
A = 28.125 * pi cm^2
A = 88.357 cm^2
Step-by-step explanation:
Area of a sector is 1/2 r^2 theta where theta is in radians
convert 45 degrees to radians
theta = 45 * pi/180 = pi/4
A = 1/2 * 15^2 * pi/4
A =1/2 * 225 * pi/4
A = 28.125 * pi cm^2
A = 88.357 cm^2
Answer:
x = -4 , y = 3
Step-by-step explanation:
5x - 7y = -41 ... (i)
-3x - 5y = -3 ... (ii)
Multiplying (i) by -3 and (ii) by 5 ;
-15x + 21y = 123 ... (i)
-15x - 25y = -15 ... (ii)
Subtracting (i) by (ii) ;
0 + 46y = 138
46y = 138
y = 138 ÷ 46 = 3
Returning to equation (ii) ;
-3x - 5(3) = -3
-3x = -3 + 15
-3x = 12
x = -4
I am not really sure but I think the answer is B