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katen-ka-za [31]
3 years ago
12

Leon needs to save more than $350 to buy a new bike. He has$130 saved so far, and he plans to save $20 each week until he has en

ough. The inequality below represents x, the number of weeks he must save to have the extra money needed. Which best describes the number of weeks he must save before he can buy his bike?
Mathematics
2 answers:
Yanka [14]3 years ago
3 0
$350= $130+$20x, x= amount of weeks
$350-$130=$220 $20*11=220
Answer: 11 weeks
erica [24]3 years ago
3 0
Leon needs $350
Leon has $130
Leon wants to save $20 per week
x = weeks

First, let's place what Leon needs on the left side of the equation:

$350 = ...

We know Leon as $130 saved so far, he plans to save $20 a week.
So, what you do here is add $130 to $20x. The reason why x is next to the $20 is because Leon wants to save $20 a week (the x represents the week). The reason why you add 130 is that's what Leon has saved so far. Therefore, the right side of your equation should look like this:

... = 130 + 20x

whereas 130 represents the amount saved so far, 20 represents weekly savings, x represents the number of weeks.

Put the left and right sides of the equation together and you should have:

$350 = $130 + $20x

Now, if you want to solve the equation:

Subtract 130 from both sides

  350 =  130 + 20x
- 130   - 130
-----------------------------
220 = 20x

Then, divide 20 by both sides

220 = 20x
-----   -----
20      20

11 = x

Leon needs to save up $20 for 11 weeks if he wants to buy the bike.

Want to check your answer?

Plug in 11 for x since 11 is the number of weeks.

350 = 130 + 20(11)
350 = 130 + 220
350 = 350

Answers match, therefore your answer is correct
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Answer:

the answer is B

Step-by-step explanation:

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3 years ago
A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
Fizzy Waters has been involved in multiple lawsuits regarding the alkaline substance concentration in their product and getting
ser-zykov [4K]

Answer:

Step-by-step explanation:

For the sample, n = 12

Mean, x = (158.2 + 162.8 + 161.5 + 161.2 + 166.5 + 160.1 + 158.4 + 175.6 + 159.9 + 168.8 + 161.9 + 163.7)/12 = 163.22

Variance, s² = (summation(x - mean)²/n

Summation(x - mean)² = (158.2 - 163.22)^2 + (162.8 - 163.22)^2 + (161.5 - 163.22)^2 + (161.2 - 163.22)^2+ (166.5 - 163.22)^2 + (160.1 - 163.22)^2 + (158.4 - 163.22)^2 + (175.6 - 163.22)^2 + (159.9 - 163.22)^2 + (168.8 - 163.22)^2 + (161.9 - 163.22)^2 + (163.7 - 163.22)^2 = 273.5368

Variance, s² = 273.5368/12 = 22.79

This is a test for a single variance. We would set up the test hypothesis.

For the null hypothesis,

H0: σ² ≥ 25

For the alternative hypothesis,

H1: σ² < 25

The formula for determining the test statistic,x² is

x² = (n - 1)s²/σ²

Where n - 1 is the degree of freedom, df.

df = 12 - 1 = 11

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Cl = 1 - alpha(level of significance)

alpha = 1 - 0.9 = 0.1

The critical value from the chi-square distribution table is 17.28. Since 17.28 > 10.0276, we would reject the null hypothesis. Therefore, the filling machine does not need repair because the variance of the process is not more than 25 oz.

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