Question

Paisley is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 22 meters from the building. The angle of elevation from her eyes to the roof (point A) is 29°, and the angle of elevation from her eyes to the top of the antenna (point B) is 42°. If her eyes are 1.74 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest meter if necessary.

Answer 1

Using the tangent ratio, the height of the antenna, to the nearest meter, is AB = 8 m.

What is the Tangent Ratio?

Tangent ratio is expressed as: tan ∅ = opposite/adjacent (TOA).

The information given has been sketched in the diagram attached below.

Find AC using the tangent ratio. Thus, we would have:

tan 29 = AC/CD

Substitute

tan 29 = AC/22

AC = tan 29 × 22 = 12.2 m.

Find BC using the tangent ratio:

tan 42 = BC/DC

Substitute

tan 42 = BC/22

BC = tan 42 × 22 = 19.8 m.

The height of the antenna, AB = BC - AC = 19.8 - 12.2 ≈ 8 m.

Learn more about tangent ratio on:

brainly.com/question/1592477