Answer:
Hey there!
This is not a valid experiment because the sunshine each section received were not equal.
Let me know if this helps :)
Answer:
12 miles
Step-by-step explanation:
The problem above is related to the topic on "Equivalent Ratios." The missing term above is <em>"the number of miles that the vehicle can travel per gallon of gasoline."</em> In order to find this term, you have to use the "cross products."
Let n be the missing term.
x n =
x 1 gallon
- n =
÷ 
- n =
x 
Therefore, the vehicle can travel 12 miles per gallon of gasoline.
Answer:

Step-by-step explanation:
The equation of the given straight line is 2x - 3y + 15 = 0.
Now, we can express the equation as 3y = 2x + 15
⇒
..........(1)
The equation is in slope-intercept form and the slope is =
Therefore, the equation of a straight line which is perpendicular to (1) is
{Where c is any constant}
{Since, the product of slopes of two perpendicular straight lines is -1}
Now, putting c = 1, we get the equation as
. (Answer)
Answer:
The value of ln e^4 is 4 so the answer is D 4 P.S i know its right i just took the test
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let's first find the exponential function that models the situation in year one. The exponential standard form is
where a is the initial value and b is the growth/decay rate in decimal form. If it is growth it is added to 100% of the initial value; if it is decay it is taken away from 100% of the initial value. We are told that the number of cars in year one was 80 million, so
a = 80 (in millions)
If b is increasing by 10%, then we are adding that amount to the initial 100% we started with to give us 100% + 10% = 110% or, in decimal form, 1.1
The model for our situation is
where y is the number of cars after x years goes by. We want to find the difference between years 3 and 2, so we will use our model twice, replacing x with both a 2 and then a 3 and subtracting.
When x = 2:
and
y = 80(1.21) so
y = 96.8 million cars
When x = 3:
and
y = 80(1.331) so
y = 106.48 million cars
The difference between years 3 and 2 is
106.48 - 96.8 = 9.68 million cars