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Wittaler [7]
2 years ago
5

Put the following items in order from most expensive to least expensive. Item Base Price Change Direction Blender $29. 73 9% Mar

kdown Hat $14. 16 77% Markup Ink $20. 17 27% Markup Heater $28. 46 22% Markdown a. Blender, heater, ink, hat b. Blender, ink, hat, heater c. Ink, hat, blender, heater d. Ink, heater, blender, hat.
Mathematics
1 answer:
Furkat [3]2 years ago
4 0

Putting the considered items in order from most expensive to least expensive item gives the order as shown by: Option b. Blender, ink, hat, heater

<h3>What is Markup and Markdown?</h3>

Markup is the amount that will be increased in the original price of the considered thing.

Markdown is the amount that will be decreased from the original price of the considered thing.

Think of "up" and "down" as increasing and decreasing prices respectively.

<h3>How to find the percentage from the total value?</h3>

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

\dfrac{a}{100} \times b

For this case, the base prices and the chage in price is given as:

Item                Base Price                    Change Direction

Blender            $29.73                           9% Markdown

Hat                   $14.16                             77% Markup

Ink                    $20.17                            27% Markup

Heater             $28.46                           22% Markdown

Calculating the resultant price:

  • Case 1: Blender:

Resultant price = 29.73 - 9% of 29.73

P= 29.73 - \dfrac{29.73}{100}\times 9\\\\P = 27.0543 \: \: \text{dollars}

  • Case 2: Hat:

Resultant price = 14.16 + 77% of 14.16

P= 14.16+\dfrac{14.16}{100}\times 77\\\\P = 25.0632\: \: \text{dollars}

  • Case 3: Ink:

Resultant price = 20.17 + 27% of 20.17

P= 20.17+\dfrac{20.17}{100}\times 27\\\\P = 25.6159\: \: \text{dollars}

  • Case 4: Heater:

Resultant price = 28.46 - 22% of 28.46

P= 28.46- \dfrac{28.46}{100}\times 22\\\\P = 25.0448 \: \: \text{dollars}

Thus, putting the considered items in order from most expensive to least expensive item gives the order as shown by: Option b. Blender, ink, hat, heater

Learn more about percent here:

brainly.com/question/11549320

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Step-by-step explanation:

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5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P...(1)

12,066.60 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{4} - P ...(2)

Dividing equation (2) by (1), we have;

\dfrac{12,066.60}{5,460} = \dfrac{P \cdot \left ( \left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1\right )}{P \cdot \left (\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 \right ) } =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1  }

Let \  \left ( 1 + \dfrac{r}{100} \right ) ^{2} = x, we \ get;

\dfrac{12,066.60}{5,460} =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1  } = \dfrac{x^2 - 1}{x - 1}

∴ 12,066.60 × (x - 1) = 5,460 × (x² - 1) = 5,460 × (x - 1) ×(x + 1)

∴ 12,066.60 × (x - 1)/(x - 1) = 5,460 × (x + 1)

12,066.60/5,460 = x + 1

x =  12,066.60/5,460 - 1 = 1.21 = 121/100

x = 121/100

\left ( 1 + \dfrac{r}{100} \right ) ^{2} = x = \dfrac{121}{100}

1 + \dfrac{r}{100}   =\sqrt{ \dfrac{121}{100}} = \dfrac{11}{10}

We get

\dfrac{12,066.60}{5,460} =\dfrac{221}{100}

\therefore \dfrac{12,066.60}{5,460} =\dfrac{221}{100} = \left ( 1 + \dfrac{r}{100} \right ) ^{2}

1 + \dfrac{r}{100} = \sqrt{ \dfrac{221}{100} } = \dfrac{\sqrt{221} }{10}

\dfrac{r}{100} = \dfrac{\sqrt{221} }{10} - 1

\dfrac{r}{100}   = \dfrac{11}{10} - 1 = \dfrac{1}{10} = 0.1

r = 100 × 0.1 = 10%

r = 10%

Therefore, we have;

5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P = P \times \left ( 1 + 0.1\right ) ^{2} - P

5,460  = P \times \left ( 1 + 0.1\right ) ^{2} - P = P \times \left (\left ( 1 + 0.1\right ) ^{2} - 1\right) = P \times \dfrac{21}{100}

P = \dfrac{100}{21} \times 5,460 = 26,000

The principal = Rs. 26,000

The compound interest in 3 years is therefore;

CI_3 = 26,000 \times \left ( 1 + \dfrac{10}{100} \right ) ^{3} - 26,000= 8606

The difference, 'd', between the principal and the compound interest in three years, is given as follows;

d = P - CI₃

d = 26,600 - 8606 = 17994

The difference between the principal and the compound interest in three years, d = Rs 17,994.

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