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lora16 [44]
2 years ago
15

When it is 8:00 a.m. in damascus, it is 4:00 p.m. in vladivostok. if your plane departs from vladivostok at 10:45 a.m. local tim

e and lands in damascus at 12:30 p.m. local time, how long was the flight? a. 1 hour, 45 minutes b. 5 hours, 45 minutes c. 9 hours, 45 minutes d. 13 hours, 45 minutes
Mathematics
2 answers:
morpeh [17]2 years ago
7 0

Answer:

When it is 8:00 a.m. in Damascus, it is 4:00 p.m. in Vladivostok. If your plane departs from Vladivostok at 10:45 a.m. local time and lands in Damascus at 12:30 p.m. local time, how long was the flight?

a.   1 hour, 45 minutes

b.   5 hours, 45 minutes

<u>c.   9 hours, 45 minutes<<< CORRECT</u>

d.   13 hours, 45 minutes

Step-by-step explanation:

2022 Edge TOPIC TEST

Ipatiy [6.2K]2 years ago
5 0

The length of the considered flight in terms of time is given by: Option C. 9 hours, 45 minutes

<h3>What is local time?</h3>

Local time refers to the time of a particular region. The term local refers that whoever is noticing the time and calling it local time means that the person is telling about the time of the place where they're currently staying.

For this case, we're provided that:

When its 8:00 a.m. Damascus it its 4:00 pm in Vladivostok, so the time in Vladivostok is 8 hours ahead of Damascus (or 16 hours behind).

Assuming its 8 hours ahead, as the plane departs from 10:45 am from Vladivostok, and lands in Damascus at 12:30 pm, so 12:30 pm + 8 hours gives 8:30 pm in Vladivostok.

So, the plane departed at 10:45 am of Vladivostok and lands at 8:30 pm in Vladivostok, so it took 9 hours and 45 minutes for his flight to go from Vladivostok to Damascus. (since difference between 8:30 pm and 10:30 am (from 10:30 am to 8:30 pm) is of 9 hours 45 minutes)

Thus, the length of the considered flight in terms of time is given by: Option C. 9 hours, 45 minutes

Learn more about timezones here:

brainly.com/question/4054255

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Answer: Option A

P = \$\ 1.05

Step-by-step explanation:

If we have 5 cans of ketchup they cost $ 5.25. Then the unit price of cans is what each can costs individually.

The unit price should then be less than $ 5.25, and that is the price for 5 cans and we want to know the price for just one can of ketchup.

Then to calculate the price of each can divide the price of the 5 cans by 5.

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Step-by-step explanation:

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For any triangle ABC note down the sine and cos theorems ( sinA/a= sinB/b etc..)
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Answer:

Step-by-step explanation:

Law of sines is:

(sin A) / a = (sin B) / b = (sin C) / c

Law of cosines is:

c² = a² + b² − 2ab cos C

Note that a, b, and c are interchangeable, so long as the angle in the cosine corresponds to the side on the left of the equation (for example, angle C is opposite of side c).

Also, angles of a triangle add up to 180° or π.

(i) sin(B−C) / sin(B+C)

Since A+B+C = π, B+C = π−A:

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Using angle shift property:

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Using angle sum/difference identity:

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Distribute:

(sin B cos C) / sin A − (cos B sin C) / sin A

From law of sines, sin B / sin A = b / a, and sin C / sin A = c / a.

(b/a) cos C − (c/a) cos B

From law of cosines:

c² = a² + b² − 2ab cos C

(c/a)² = 1 + (b/a)² − 2(b/a) cos C

2(b/a) cos C = 1 + (b/a)² − (c/a)²

(b/a) cos C = ½ + ½ (b/a)² − ½ (c/a)²

Similarly:

b² = a² + c² − 2ac cos B

(b/a)² = 1 + (c/a)² − 2(c/a) cos B

2(c/a) cos B = 1 + (c/a)² − (b/a)²

(c/a) cos B = ½ + ½ (c/a)² − ½ (b/a)²

Substituting:

[ ½ + ½ (b/a)² − ½ (c/a)² ] − [ ½ + ½ (c/a)² − ½ (b/a)² ]

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From law of cosines, we know:

b² = a² + c² − 2ac cos B

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1/(2bc) (a²b + bc² − b³ + a²c + b²c − c³)

Rearrange:

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Factor (use sum of cubes):

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(b + c)/(2bc) (2bc + a² − b² − c²)

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(b + c) + (b + c)/(2bc) (a² − b² − c²)

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2(b + c) sin²(A/2)

(iii) (b + c) cos A + (a + c) cos B + (a + b) cos C

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Common denominator:

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We have to distribute, which is messy.  To keep things neat, let's do this one at a time.  First, let's look at the a² terms.

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c² (ab + ac + ab + bc − ac − bc)

2abc²

Substituting:

(2a²bc + 2ab²c + 2abc²) / (2abc)

2abc (a + b + c) / (2abc)

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