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lora16 [44]
2 years ago
15

When it is 8:00 a.m. in damascus, it is 4:00 p.m. in vladivostok. if your plane departs from vladivostok at 10:45 a.m. local tim

e and lands in damascus at 12:30 p.m. local time, how long was the flight? a. 1 hour, 45 minutes b. 5 hours, 45 minutes c. 9 hours, 45 minutes d. 13 hours, 45 minutes
Mathematics
2 answers:
morpeh [17]2 years ago
7 0

Answer:

When it is 8:00 a.m. in Damascus, it is 4:00 p.m. in Vladivostok. If your plane departs from Vladivostok at 10:45 a.m. local time and lands in Damascus at 12:30 p.m. local time, how long was the flight?

a.   1 hour, 45 minutes

b.   5 hours, 45 minutes

<u>c.   9 hours, 45 minutes<<< CORRECT</u>

d.   13 hours, 45 minutes

Step-by-step explanation:

2022 Edge TOPIC TEST

Ipatiy [6.2K]2 years ago
5 0

The length of the considered flight in terms of time is given by: Option C. 9 hours, 45 minutes

<h3>What is local time?</h3>

Local time refers to the time of a particular region. The term local refers that whoever is noticing the time and calling it local time means that the person is telling about the time of the place where they're currently staying.

For this case, we're provided that:

When its 8:00 a.m. Damascus it its 4:00 pm in Vladivostok, so the time in Vladivostok is 8 hours ahead of Damascus (or 16 hours behind).

Assuming its 8 hours ahead, as the plane departs from 10:45 am from Vladivostok, and lands in Damascus at 12:30 pm, so 12:30 pm + 8 hours gives 8:30 pm in Vladivostok.

So, the plane departed at 10:45 am of Vladivostok and lands at 8:30 pm in Vladivostok, so it took 9 hours and 45 minutes for his flight to go from Vladivostok to Damascus. (since difference between 8:30 pm and 10:30 am (from 10:30 am to 8:30 pm) is of 9 hours 45 minutes)

Thus, the length of the considered flight in terms of time is given by: Option C. 9 hours, 45 minutes

Learn more about timezones here:

brainly.com/question/4054255

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A 2-liter bottle of juice costs $2.80. A box containing six 12-liter bottles sells for $3.90. Which option has a higher cost per
barxatty [35]

Answer:The first option has a higher cost per liter and the required cost is $1.40 per liter.

Step-by-step explanation:

Step-by-step explanation:  Given that a 2 liter bottle of juice cost $2.80. A box containing six 12 liter bottle sells for $3.90.

We are to select the option that has a higher cost per liter.

We will be using the UNITARY method to solve the given problem.

Option (1) :  

The cost of 2 liter bottle of juice = $2.80.

So, the cost of 1 liter bottle of juice will be

Option (2) :  

The cost of six 12 liters bottle of juice = $3.90.

So, the cost of 1 liter bottle of juice will be

Since 0.05>1.40, so the option of 2 liter bottle costing $2.80 has a higher cost per liter.

And, the required cost is $1.40 per liter.

7 0
2 years ago
Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i
kolezko [41]

Answer:

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

Step-by-step explanation:

Data given and notation

Data:    801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=811 represent the sample mean  

s=19.647 represent the standard deviation for the sample

n=5 sample size  

\mu_o =750 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:  

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

What do you conclude?  

Compute the p-value  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

4 0
3 years ago
Find the discontinues<br> F(x)= sin(x^2-2)
maks197457 [2]
.15(pi)=24-68(0) that is the answer hope it helps
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A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 8% of t
IRINA_888 [86]

Answer: 0.206

Step-by-step explanation: the probability of employees that needs corrective shoes are =8%= 8/100 = 0.08

Probability of employees that needs major dental work = 15% = 15/100 = 0.15

Probability of employees that needs both corrective shoes and dental work = 3% = 3/100 = 0.03

The probability that an employee will need either corrective shoes or major dental work = (Probability an employee will need correct shoes and not need dental work) or (probability that an employee will need dental work or not corrective shoes)

Probability of employee not needing corrective shoes = 1 - 0.08 = 0.92

Probability of employee not needing dental work = 1 - 0.15 = 0.85

The probability that an employee will need either corrective shoes or major dental work = (0.08×0.85) + (0.15×0.92) = 0.068 + 0.138 = 0.206 = 20.6%

The probability that an employee will need either corrective shoes or dental work = 0.206.

Please note that the word "either" implies that we must choose one of the two options (corrective shoes or dental work) and not both.

5 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

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~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
1 year ago
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