All categories

3 years ago

The sum of 2 numbers is 50. The sum of 1/4 of the first number and 2/3 of the second number is 25.What are the numbers?

Mathematics

1 answer:

tino4ka555 [31]3 years ago

6 0

Answer:

First number: 20

Second number: 30

Step-by-step explanation:

First#: x

Second#: y

Constraints:

x + y = 50

1/4x + 2/3y = 25

Isolate variable y:

x + y = 50

-1/4 (x + y = 50 )

-1/4x - 1/4y = -12.5

Add equations the two equations to eliminate x:

-1/4x - 1/4y = -12.5

1/4x + 2/3y = 25

_________________

5/12y = 12.5

5y = 150

y = 30

Substitution to find x:

x + y = 50

x + 30 = 50

x = 20

You might be interested in

A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than One-fifth?

nignag [31]

Answer:

choosing 1 blue marble, choosing one white marble not replacing it and choosing a blue and lastly choosing one white marble.

Step-by-step explanation:

4 0

3 years ago

we want a ratio of orange seashells and pink seashells to be 3:7. we should use 40 seashells.how many orange shells should we pa

dybincka [34]

Add the ratios together: 3+7=10. The ratio means that there are 3/10×40=12 orange seashells and 7/10×40=28 pink seashells.

7 0

3 years ago

What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)

svlad2 [7]

Answer:

The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

Step-by-step explanation:

Given : Expression $7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

To Simplified : The expression

Solution :

Step 1 - Write the expression

$7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

Step 2- Simplify the roots and re-write as

$16=2^3\times2$ and $8=2^3$

$7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}$

Step 3- Solve the multiplication

$7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}$

Step 4- Taking $\sqrt[3]{2x}$ common from first two terms

$\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}$

$\sqrt[3]{2x}-6\sqrt[3]{x}$

Therefore, The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

5 0

3 years ago

Read 2 more answers

Please please please need help on 3 and 4 I’m really lost on them

Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

Step-by-step explanation:

Given polynomial function is $f(x)=x^5-3x^3-2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$x^5-3x^3-2=0$

By synthetic division

| 1 0 -3 0 -2

-1 | 0 -1 1 2 2

|_________________

1 -1 -2 2 0

Therefore x=-1 is a zero

$x^3-x^2-2x+2=0$

| 1 -1 -2 2

1 | 0 1 0 2

|___________________

1 0 -2 0

x=1 is the zero

$x^2 -2 =0$

$x=\pm\sqrt{2}$

$x=\sqrt{2}$ and

$x=\sqrt{-2}$

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is $f(x)=(x-4)(2x-1)^2(x-2)^2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$(x-4)(2x-1)^2(x-2)^2=0$

$(x-4)=0$ (or) $(2x-1)^2=0$ or $(x-2)^2=0$

Therefore x=4, $x=\frac{1}{2}$ of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

5 0

3 years ago

mestny [16]

Answer:

∠p and ∠s; ∠q and ∠r [ both triangles are similar, the second triangle is smaller version of the other triangle and tilted right ]

5 0

2 years ago

Read 2 more answers