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Drupady [299]
2 years ago
14

Given: Rhombus ABCD. If mBAD is 64 degrees, then the mDCA is ___ degrees.

Mathematics
1 answer:
Marta_Voda [28]2 years ago
6 0

Answer: 32 degrees

Step-by-step explanation:

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A hot air balloon is flying at and altitude of 2101 feet. If the angle of depression from the pilot in the balloon to a house on
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The problem is modelled as right angle triangle, shown in the diagram below

The distance between the pilot and the house is labelled as x

Using the trigonometry ratio of sine
sin(31)= \frac{opposite}{hypotenuse}
sin(31)= \frac{2010}{x}
x= \frac{2101}{sin(31)} = 4079.3 ft

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3 years ago
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(4, 1) the process is shown in the following picture

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1/2(4x-6y)
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3 years ago
In the book Business Research Methods, Donald R. Cooper and C. William Emory (1995) discuss a manager who wishes to compare the
S_A_V [24]

Answer:

Null hypothesis is: U1 - U2 ≤ 0

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Step-by-step explanation:

The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.

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Let U2 = mean sales by type B trainees

Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0

This implies that type A training does not result in higher mean weekly sales than type B training.

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4 0
3 years ago
Solve the equation on the<br> interval [0, 27r).<br> 4(sin x)2 - 2 = 0
Ket [755]

4[sin(x)]^2 - 2 = 0\implies 4[sin(x)]^2=2\implies [sin(x)]^2=\cfrac{2}{4}\implies [sin(x)]^2=\cfrac{1}{2} \\\\\\ sin(x)=\pm\sqrt{\cfrac{1}{2}}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)\implies x=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)

x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill

Check the picture below.

4 0
2 years ago
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