To find the area of a sector of a circle use the next formula:
As the given circle has a outside angle 90º (it is not part of the sector of the circle) subtract the 90º from 360º (total angle of a circle) to find the angle of the sector:
Find the area of the sector with angle 270º:
Answer : 2√3
<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .
Now we may use Pythagoras theorem as ,
→ AB² = BC² + AC²
→ 4² = 2² + x²
→ 16 = 4 + x²
→ x² = 16-4
→ x² = 12
→ x =√12 = √{ 3 * 2²}
→ x = 2√3
<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>
I hope this helps.
