The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
Learn more about distance traveled by a vehicle here: brainly.com/question/6504879
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Answer:
Step 4 : he should have divided both sides by negative seven
Step-by-step explanation:
Plug in (7, 12) for x and y in the equation.
12 = 2(7) + 1
12 = 14 + 1
12 ≠ 15
Therefore, (7, 12) is not on the straight line equation.
Answer:
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
Step-by-step explanation:
Given:
Number is
200.06
For option A)
2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
= 200 + 0 + 0 + 0.06
= 200.06
Which is CORRECT.
For option B)
2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000
= 200 + 0 + 0 + 0.006
=200.006
Which is INCORRECT.
For option C)
2 × 100 + 6 × 1/10
= 200 + 0.6
= 200.6
Which is INCORRECT.
For option D)
2 × 100 + 6 × 1/100
= 200 + 0.06
= 200.06
Which is CORRECT.
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
(x + 5)²z
(x + 5)(x+ 5)z
(x² + 5x + 5x + 25)z
(x² + 10x + 25)z
(x²)z + (10x)z + (25)z
x²z + 10xz + 25z
