Answer: 61.16 ft
Step-by-step explanation:
We can think in this situation as a triangle rectangle.
where:
The height of the tree is one cathetus
The shadow of the tree is the other cathetus.
We know that the angle of elevation of the sun is 78°, an angle of elevation is measured from the ground, then the adjacent cathetus to this angle is the shadow of the tree. And the opposite cathetus will be the height of the tree.
Now we can remember the relationship:
Tg(A) = (opposite cathetus)/(adjacent cathetus)
Where:
A = 78°
Adjacent cathetus = 13ft
opposite cathetus = height of the tree = H
Then we have the equation:
Tg(78°) = H/13ft
Tg(78°)*13ft = H = 61.16 ft
using pythagorean theorem
a^2 + b^2 = c^2
(12x)^2 + (16x)^2 = 10^2
square each term
144x^2 + 256x^2 = 100
combine like terms
400 x^2 = 100
divide by 400 on each side
x^2 = 1/4
take the square root on each side
x = 1/2
Answer: x=1/2
Includes critical information you need to identify the chemical
, Includes warnings about the chemical
, Legible are the requirements for chemical labels
<u>Step-by-step explanation:</u>
Labels need to produce guidance on how to manage the chemical so that chemical users are notified about how to guard themselves. That data about chemical hazards be dispatched on labels using quick visual notations (Legible) to inform the user, granting instant identification of the hazards.
Labels, as described in the HCS, are a relevant group of written, printed or graphic information elements concerning a hazardous chemical that are attached to, printed on, or added to the immediate container of a hazardous chemical, or to the outside packaging.
36
Step-by-step explanation:
4 5/8*3 is 13.875
500 decided by 13.875 is a little over 36, so you can make 36 full ribbons
