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GarryVolchara [31]
2 years ago
12

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighb

orhood. they are: 2,400; 1,750; 1,900; 2,500; 2,250; 2,100 which of the following represents the numerator in the calculation of variance and standard deviation? (225)2 (–425)2 (–275)2 (325)2 (75)2 (–75)2 = 423,750 (650)2 (–150)2 (–600)2 (250)2 (150)2 (–300)2 = 980,000 (250)2 (–400)2 (–250)2 (350)2 (100)2 (–50)2 = 420,000 what is the variance? what is the standard deviation, rounded to the nearest whole number?
Mathematics
1 answer:
Sedbober [7]2 years ago
8 0

Option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

<h3>What are the variance and standard deviation?  </h3>

In statistics, variance is a measure of the variation of data from the mean, whereas standard deviation is the measure of the normal distribution of statistical data.

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighborhood.

2,400; 1,750; 1,900; 2,500; 2,250; 2,100

we need to find which of the following represents the numerator in the calculation of variance and standard deviation.

(225)^{2} + (–425)^{2}+ (–275)^{2} + (325)^{2} + (75)^{2}+ (–75)^{2} = 423,750

(650)^{2} + (–150)^{2} + (–600)^{2} + (250)^{2} + (150)^{2} + (–300)^{2} = 980,000

(250)^{2} + (–400)^{2} + (–250)^{2} + (350)^{2} + (100)^{2} + (–50)^{2} = 420,000  

92416.60

The variance is 84000

The standard deviation is 290

mean = (2400+1750+1900+2500+2250+2100)/6

mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250

1750-2150 = -400

1900-2150 = -250

2500-2150 = 350

2250-2150 = 100

2100-2150 = -50

The differences are 250, -400, -250, 350, 100, -50

Then you square those values and add up the squares

(250)^2 +  (-400)^2 +  (-250)^2 +  (350)^2 +  (100)^2 +  (-50)^2 = 420,000

Hence, option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

Learn more about variance;

brainly.com/question/14116780

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Solve x2 + 7x + x2 + 7x + 9 = 3​
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How does the speed of a runner vary over the course of a marathon (a distance of 42.195 km)? Consider determining both the time
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Answer:

The observed typical difference value of mode is 100 seconds approximately.

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

Step-by-step explanation:

Fundamentals

Consider that there are x favorable cases to an event E, out of a total of n cases. Then, the probability of that event is written as:

P(E)=  

Total number of cases /Number of favorable cases =  x/n

A histogram is constructed for continuous data, which is divided into classes called bins. The shape of the distribution can be determined from the histogram.

step 1

The provided histogram indicates time difference on xx -axis and frequency of runners on yy -axis. To determine the typical difference value, identify the peaks of the graph.

The histogram is skewed towards right side. The graph indicates that there are few outliers around 700 seconds. For a typical difference value, the value of mode is considered.

The graph indicates that the value of mode is 100 seconds approximately.

The observed typical difference value of mode is 100 seconds approximately.

Explanation

From the histogram, the typical difference value is obtained on the basis of guessing the value of mode which has been approximated to be around 100 seconds.

Step 2

From the histogram, it can be estimated that there are around 10 runners which has negative difference which means approxi8matley 10 runners ran the late distance more quickly than the early distance,

The approximate sample size can be calculated as:

Sample size=90+190+180+160+120+80+60+40+30+20

Thus, the proportion of runners is obtained as:

\begin{array}{c}\\p = \frac{{\left( \begin{array}{l}\\{\rm{Number of runners who has }}\\\\{\rm{negative time difference}}\\\end{array} \right)}}{{{\rm{Total sample size}}}}\\\\ = \frac{{10}}{{970}}\\\\ = 0.01\\\end{array}  

p=  <u> </u>Number of runners who has

<u>     negative time difference   </u>

      Total sample size

​  

=10/970

=0.001

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

EXPLANATION

The obtained proportion is 0.01. It indicates that there are approximately 1% of the runners who ran late distance more quickly than the early distance is very few.

​  

​  

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Answer:

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