2 years ago

Help!

Mathematics

2 answers:

Alenkasestr [34]2 years ago

7 0

Answer:

Your right the answer is 74

Step-by-step explanation:

oee [108]2 years ago

3 0

It should be 74 if not right srry

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Convert the integral below to polar coordinates and evaluate the integral.

White raven [17]

I suppose the integral is

$\displaystyle\int_0^5\int_y^{\sqrt{25-y^2}} xy\,\mathrm dx\,\mathrm dy$

The integration region corresponds to a sector of a cirlce with radius 5 subtended by a central angle of π/4 rad. We can capture this region in polar coordinates by the set

$R=\left\{(r,\theta)\mid0\le r\le5,0\le\theta\le\dfrac\pi4\right\}$

Then $x=r\cos\theta$ , $y=r\sin\theta$ , and $\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$ . So the integral becomes

$\displaystyle\iint_Rxy\,\mathrm dx\,\mathrm dy=\int_0^{\pi/4}\int_0^5r^3\sin\theta\cos\theta\,\mathrm dr\,\mathrm d\theta=\frac{625}{16}$

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Step-by-step explanation:

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2 years ago

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The answer is

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