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2 years ago

The following table shows the first segment of a five-year amortization schedule.

1 answer:

4 0

After one year of payments, the amount need to be paid to interest is $1100.42 if the first segment of a five-year amortization schedule is a 5-year amortization schedule option (a) is correct.

<h3>What is a loan amortization schedule?</h3>

It is defined as the systematic way of representation of loan payments according to the time in which the principal amount and interest mentioned in a list manner.

We have a table given that showing a first segment of a five-year amortization schedule that has a 5-year amortization schedule and the amount of interest paid for months 1 through 12.

As the loan amount is not mentioned in the question, we are assuming the loan amount is $1184.6

Therefore, loan amount = $1184.6

The outstanding amount at the end of one year, which is 12 months, is shown in the table as $84.18

After one year of payments, the amount need to be paid to interest:

= Loan amount - Outstanding amount after 12 months

= 1184.6 - 84.18

= $1100.425

Thus, after one year of payments, the amount need to be paid to interest is $1100.42 if the first segment of a five-year amortization schedule is a 5-year amortization schedule option (a) is correct.

Learn more about the amortization schedule here:

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the first four terms of a geometric progression are 2,10,50,250 a) write down the common ratio of the progression b) write down

VLD [36.1K]

Answer:

The common ratio is 5 and the 5th term is 1250

Step-by-step explanation:

The common ratio is given by

r=U(2)/U (1)

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3 years ago

If you were to use the “Completing the Square” method to solve the equation below for k, what number would you add to both sides

Makovka662 [10]

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The number you would add to both sides of the equation to use the "Completing the Square" method would be 16.

Step-by-step explanation:

To find the number to add to both sides of an equation to complete the square, divide the first-degree term's coefficient by 2 and square your remainder. In this case, the coefficient of the first-degree term is -8. After dividing by 2 and squaring it, you'll get 16, so that is the number you must add to both sides of the equation in order to complete the square.

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3 years ago

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Verify csc^2t-cos t sect= cot^2 t

Ymorist [56]

Rewriting the left hand side,

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= (1/sin²t)-(cost)(1/cost)

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2 years ago

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

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4 years ago