???????I don't get it

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

To fill the squares look for the one filled in column/row/diagonal and figure out its sum.
All other columns/rows/diagonals must be equal to that, so whenever there is a column/row/diagonal with a single missing value you can add the others up and calculate the missing value.
So you have to find those single missing value columns/rows/diagonals, fill them out and continue with the next one until the whole square is filled in.

You might be interested in

Answer fast ..................

Kitty [74]

Answer:

Please check the explanation.

Step-by-step explanation:

Ascending Order:

When we talk about the numbers to be arranged in ascending order, it means the numbers need to be arranged from smallest to largest.

For example, if we have to arrange the numbers from 1 to 5 in ascending order.

It means, the ascending order will be: 1, 2, 3, 4, 5

Now, let us arrange the given numbers in ascending order.

a) 2234 to 2238 2234 2235 2236 2237 2238

b) 4099 to 4103 4099 4100 4101 4102 4103

c) 3298 to 3302 3298 3299 3300 3301 3302

d) 7269 to 7273 7269 7270 7271 7272 7273

e) 6354 to 6358 6354 6355 6356 6357 6358

f) 8379 to 8383 8379 8380 8381 8382 8383

g) 7365 to 7369 7365 7366 7367 7368 7369

5 0

2 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒