Question

According to a recent survey of adults, approximately 62% carry cash on a regular basis. The adults were also

Answer 1

According to the probabilities given, it is found that the correct option regarding the independence of the events is given by:

No, P(carry cash) != P(carry cash|have children).

What is the probability of independent events?

If two events, A and B, are independent, we have that:

$P(A \cap B) = P(A)P(B)$

Which also means that:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

In this problem, we have that:

• 62% carry cash on a regular basis, hence P(cash) = 0.62.

• 46% has children, hence P(children) = 0.46.

• Of the 46% who have children, 85% carry cash on a regular basis, hence P(cash|children) = 0.85.

Since P(carry cash) != P(carry cash|have children), they are not independent.

More can be learned about the probability of independent events at brainly.com/question/25715148