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aleksandr82 [10.1K]
2 years ago
11

In the activity, when na lost an e- it shrank and the cl+ grew in size. does that say anything about the location of the electro

n before and after it was transferred?
SAT
1 answer:
Vadim26 [7]2 years ago
5 0

Since the electron that is lost is on the valence shell of sodium, the size of sodium will shrink while the size of chlorine will increase.

<h3>Ionic bonding</h3>

Ionic bonding is said  to occur when a  metal looses an electron to a nonmetal. The resulting compound is actually an ion pair.

For the formation of sodium chloride, a sodium atom looses an electron which is present on its valence shell while chlorine accepts this electrons into its valence shell as a result, the size of sodium will shrink while the size of chlorine will increase.

Learn more about ionic bonding: brainly.com/question/11527546

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Explanation:

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2 years ago
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tigry1 [53]

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Nezavi [6.7K]
This is an easy question. you just have to divide.
420÷6.82= 61.5
but because they are individual stocks and you can't have half a stock, you round it up to the nearest whole number
so the answer is 61
hope I helped:)
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Answer: Haploid + Haploid = Diploid :)

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Explanation:

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