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2 years ago

Ransomware as a service has allowed the increase of:.

Computers and Technology

1 answer:

Montano1993 [528]2 years ago

6 0

Ransomware as a Service has allowed the increase of ransomware infections globally.

<h3>What is a Ransomware as a Service?</h3>

Ransomware as a Service is a type of business association between ransomware operators and affiliates. These affiliates pay to launch ransomware attacks developed by operators.

A ransomware is a type of malicious software that infects the computer of an organization thereby restricting access to their important data unless an amount of money is paid.

Ransomware as a Service has allowed the increase of ransomware infections globally because this business model has allowed malware creators to earn from their ransomware by enlisting a network of distributors.

Therefore, ransomware as a service has allowed the increase of ransomware infections globally.

Learn more about ransomware here:

brainly.com/question/23294592

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BRAINLIEST FOR CORRECT ANSWERS PLS HELP

koban [17]

Either A or B. I would go with A but It can actually be B

5 0

3 years ago

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The alumni development office at your university uses specialized software that can be accessed from two different servers. The

Agata [3.3K]

Answer:

Round-Robin DNS

Explanation:

According to my experience in Information Technology and Networking it can be said that based on the information provided the best solution would be to set up a Round-Robin DNS. This term refers to a technique used to balance the load on a server, where a client request is sent to each server one at a time, and then the system repeats the process from the top of the request list. This prevents the server from being drowned in a sea of simultaneous requests.

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6 0

3 years ago

Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl

Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

small = num1

if num1 > num2:

small = num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

print("The GCD is "+ str(gcd))

def LCM(num1,num2):

big = num2

if num1 > num2:

big = num1

while(True):

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

print("The LCM is "+ str(lcm))

print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

if num1 > num2:

small = num2

The following iteration determines the GCD of num1 and num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

This line prints the GCD

print("The GCD is "+ str(gcd))

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

big = num2

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

if num1 > num2:

big = num1

The following iteration continues while the LCM has not been gotten.

while(True):

This if statement determines the LCM using modulo operator

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

This line prints the LCM of the two numbers

print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

See attachment for more structured program

Download txt

5 0

3 years ago

2. Create a file with the follow integer/string content and save it as fun.txt. 6 fun. 3 hello 10 <> 2 25 4 wow! Write an

Nesterboy [21]

Answer:

see explaination

Explanation:

I made use of python program to solve this.

text file name with fun.txt.

6 fun. 3 hello 10 <> 2 25 4 wow!

Program code:

import re

file = open('fun.txt','r') #for reading file

strings="" #declaring empty string

for k in file:

strings=strings+k #all character in file is storing in strings variable for do operations

pattern = '\s' #for pattern \s is for space

result = re.split(pattern, strings) #split the string with space

for k in range(len(result)): #loop through the list of string

if(k%2) == 0: #checking for integer to time of string

p=int(result[k])

print(result[k+1] *p) #print times of the string(k+1)

Check attachment for output

8 0

3 years ago

Which of these are correctly formatted Python dictionaries? Check all that apply. dict = {‘Name’: ‘Matthew’, ‘Age’: 14, ‘School’

Advocard [28]

Answer:

A. dict = {‘Name’: ‘Matthew’, ‘Age’: 14, ‘School’: ‘ABC School’}

Explanation:

Since python does not use type when declaring a variable, you must make sure you make your variables correctly or else it won't compile correctly. Lists use braces[]; Strings use quotes, "" or ''; Integers are just declared with a number(s); Dictionaries use brackets{} and inside are attributes of something. For instance, you can use dictionaries to describe ages, {'"Bryan": 6, "Alex": 13, etc.} Sort of like a json file. Dictionaries also tend to use uppercase letters when describing something. The only answer that has all the attributes correct is A. dict = {‘Name’: ‘Matthew’, ‘Age’: 14, ‘School’: ‘ABC School’}

hope i helped :D

7 0

3 years ago

Read 2 more answers