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34kurt
3 years ago
6

Declare a char array named line of size 50, and write a statement that reads in the next line of console input into this array.

(Assume the line may contain whitespace characters and the total number of the characters in the line is less than 50)
Computers and Technology
1 answer:
SashulF [63]3 years ago
8 0

Answer:

Following are the statement in the C++ Programming Language.

//set character data type variable

char line[50];

//get character input from the user

cin.get(line, 50);

Explanation:

<u>Following are the description of the statement</u>.

  • In the above statement, we set character data type array variable that is 'line' and its index value is '50' that means the following variable not contain more than 50 character elements.
  • In the other line, we get character type input in the following variable 'line' from the user through the get() method.
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Variablesallow us to manipulate data through the ___________.
gladu [14]

Answer:

Reference

Explanation:

Variables provide reference to the stored data value.

For example:

int i = 0;

Here i is a variable of type int with an initial value of 0. i is a reference to this stored value 0. Now if I want to update the data, I can do so using this reference.

i = 1;

Now the reference is used to manipulate the stored data and change it to 1. In a similar manner all updates to the value can be done using the variable reference.

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3 years ago
Assume that a gallon of paint covers about 350 square feet of wall space. Create anapplication with a main() method that prompts
Elena-2011 [213]

Answer:

import java.util.Scanner;

public class PaintClculator {

   public static void main(String[] args) {

Scanner in = new Scanner(System.in);

       System.out.println("Enter Values for length, width, and height of the room");

       double length = in.nextDouble();

       double width = in.nextDouble();

       double height = in.nextDouble();

       double wallArea = calculateWallArea(length,width,height);

       double noGallons = calculatePaint(wallArea);

       double price = price(noGallons);

       System.out.println("Price is: "+ price);

   }

   // Creating Method to Calculate Wall Area

   public static double calculateWallArea( double length, double width, double height){

       // formular for the surface area of a room Area=2*length*heigth+2*width*height+lenth*width

       double Area = 2*length*height+2*width*height+length*width;

       System.out.println("Wall Area: "+Area);

       return Area;

   }

   //Creating method to calculate amount of paint

   public static double calculatePaint(double Area){

       double noGallons = Area/350;

       System.out.println("Number of gallons: "+noGallons);

       return noGallons;

   }

   // Creating Method Calculate Price

   public static double price(double noGallons){

       return noGallons*32;

   }

}

Explanation

  1. Created Three Methods in all; calculateWallArea(), calculatePaint(), and price()
  2. Method calculateWallArea() calculates area based on this formula Area=2*length*heigth+2*width*height+lenth*width
  3. The value of Area is passed to method calculatePaint() Which calculates the number of gallons required to cover the area given that one gallon covers 350 wall space
  4. Method price() calculates and dis[plays the price by calling method calculatePaint() that returns number of gallons. since one gallon is 32$
3 0
3 years ago
mta software development fundamentals You are creating an application that accepts input and displays a response to the user. Yo
Harlamova29_29 [7]

Answer: Console-Based

Explanation:

A console based application is an application that helps in facilitating the reading and the writing of the characters from a console.

It is vital in the provision of a simple user interface for the applications that requires little interaction. Since the application accepts input and displays a response to the user and cannot create a graphical interface for this application, then it's a console based application.

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