400-126=274
400
126
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0-6 can't go into so make the 0 a 6
Then make 0-2 make 0 a 10 then a 9
Then make 4 into a 3
g(a)=33a−2; Find g(1)
g(1) means the value of a is 1. Replace a in the equation with 1 and solve.
33(1) - 2 = 33-2 = 31
g(1) = 31
3x+2 (5x-1)=11
3x +10x -2=11
3x+10x=13
13x=13
X=1
1. 9/10 + 7/9 = 81/90 + 70/90 = 151/90 = 1 61/90
2. 1/2-3/11 = 11/22-6/22 = 5/22
3. 2/5-1/15 = 6/15-1/15 = 5/15 =1/3
There are several ways this can be accomplished. Students could survey every 20 students until they've asked 100 students, or they could ask 1 or 2 people at each cafeteria table during each lunch, just for examples.