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Rudik [331]
2 years ago
10

The table shows a linear function.

Mathematics
1 answer:
Korolek [52]2 years ago
8 0

Answer:

-3

Step-by-step explanation:

:)

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What times 3 equal 19?
Gnesinka [82]

Answer:

6.3333333333333333333333333333333333333333333333333333333333

Step-by-step explanation:

19/3=6.3333333333333333333333333

6 0
3 years ago
Read 2 more answers
Tonya said that the fraction 10/12 was in simplest form. Do you agree? Why or why not?
Zarrin [17]

Answer:

NO

Step-by-step explanation:

You can reduce the fraction by dividing by 2. If you divide by 2, then you will get 5/6 which is more reduced than 10/12.

Hope  this helps plz mark brainliest if correct :D

7 0
2 years ago
Read 2 more answers
Enzo is studying the black bear population at a large national park.
Naddik [55]

Answer:

2,973

Step-by-step explanation:

The black bear population B(t), in the park is modeled by the following function:

B(t) = 2500 \cdot 2^{0.01t}

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973

There will be 2,973 black bears in 25 years time.

4 0
3 years ago
Please need help to solve this
Sunny_sXe [5.5K]
Greetings!

Convert both terms into improper fractions:
=9/1-59/8
Find the LCM.
=72/8-59/8
Simplify.
=13/8
Convert to Mixed Number.
=1 \frac{5}{8}

The second answer would be correct.

Hope this helps.
-Benjamin
5 0
3 years ago
Motor vehicles sold to individuals are classified as either cars or light trucks (including SUVs) and as either domestic or impo
Rudik [331]

Answer:

a) Probability that vehicle is Light Truck is 0.69

b) Probability that vehicle is imported car is 0.08 or 8%.

Step-by-step explanation:

Part a)

Event that vehicle is a car is given by A. Since, the vehicles can only be classified as cars or light trucks, the event that a vehicle will be light truck will be compliment of A.

i.e. Event that vehicle is a Light Truck = A^{c}

It is given that in recent year 69% of vehicles sold were light trucks, 78% were domestic, and 55% were domestic light trucks.

So, from here we can say that, if a vehicle is randomly selected from all the vehicles the probability that it would be a light truck will be:

P(Vehicle will be Light Truck) = P(A^{c}) = 69% = 0.69

Part b)

Event that vehicle is imported is given by B. We need to find the probability the a randomly chosen vehicle is an imported car i.e. we have to find probability of occurrence of events A and B together, which will be denoted as: P(A and B)

Since, P(A^{c}) = 69% = 0.69

P(A) = 1 - P(A^{c}) = 1 - 0.69 = 0.31

It is also given that 78% of vehicles were domestic. This means, the percentage/probability of imported vehicles is:

P(B) = 1 - 0.78 = 0.22

55% of vehicles were domestic light trucks. This can be expressed as:

P(A^{c}\&B^{c}), the compliment of this event will give us P(A or B).

i.e.

P(A or B) = 1 - P(A^{c} \&B^{c}) = 1 - 0.55 = 0.45

According to the addition rule of probabilities:

P(A or B) = P(A) + P(B) - P(A and B)

Substituting the calculated values gives us:

0.45 = 0.31 + 0.22 - P(A and B)

P(A and B) = 0.08

This means, the probability that vehicle is imported car is 0.08 or 8%.

4 0
2 years ago
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