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Rufina [12.5K]
3 years ago
15

SOMEBOODY HELP ME SOLVE THIS PLS!! 1.4x-10=5x+15 2.2x+2=2x+2

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:

x = -25

x = infinite solutions

Step-by-step explanation for 1:

4(-25) - 10 = 5(-25) + 15

-100 - 10 = -125 + 15

-110 = -110

Step-by-step explanation for 2:

Both equations are the exact same. So whatever number you put, the answer will be right

Readme [11.4K]3 years ago
6 0

Answer:

1)4x - 10 = 5x + 15 \\ 4x - 5x = 15 + 10 \\  - x = 25 \\ x =  - 25

2)2x + 2 = 2x + 2 \\  2x - 2x = 2 - 2 \\ 2x(1 - 1) = 0 \\ x = 0

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B2-4b+4=0 using quadratic forumla
Ivan

Trying to factor by splitting the middle term   

Factoring <span> b2-4b+4</span> 
The first term is, <span> <span>b2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -4b </span> its coefficient is <span> -4 </span>.
The last term, "the constant", is <span> +4 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span>  1 • 4 = 4</span> 

Step-2 : Find two factors of  4  whose sum equals the coefficient of the middle term, which is  <span> -4 </span>.
<span><span>     </span></span>

<span><span>-4   +   -1   =   -5</span><span>     -2   +   -2   =   -4   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  -2 
                     <span>b2 - 2b</span> - 2b - 4

Step-4 : Add up the first 2 terms, pulling out like factors :
                    b • (b-2)
              Add up the last 2 terms, pulling out common factors :
                    2 • (b-2)
Step-5 : Add up the four terms of step 4 :
                    (b-2)  •  (b-2)
             Which is the desired factorization

8 0
3 years ago
Read 2 more answers
Hello!
tankabanditka [31]

Answer:

2520

Step-by-step explanation:

LCM(4, 7, 8, 9, 10, 12) = 2520

5 0
2 years ago
Read 2 more answers
Solve this equation: -3r -6(-7-10r)
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Answer: 57r + 42

Step by step explanation:

-3r - 6(-7 - 10r)

Distribute -6 through the parenthesis

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Collect the like terms

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3 years ago
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

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Answer:

A. 138

Step-by-step explanation:

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