Question

What are the exact solutions of x2 − 3x − 5 = 0, where x equals negative b plus or minus the square root of b squared minus 4 times a times c all over 2 times a? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Answer 1

Answer:

• B. x = the quantity of 3 plus or minus the square root of 29 all over 2

Step-by-step explanation:

Given equation

• x² - 3x - 5 = 0

The roots are

• $x=\cfrac{-b+- \sqrt{b^2-4ac} }{2a}$

Substitute values into equation

• $x=\cfrac{3+- \sqrt{(-3)^2-4(1)(-5)} }{2(1)} =\cfrac{3+- \sqrt{9+20} }{2} =\cfrac{3+- \sqrt{29} }{2}$

This is matching the option B