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scoray [572]
2 years ago
8

Segment AB has endpoints at A(-7,2) and b(9,-6). Point P lies on AB such that AP:BP=3:1

Mathematics
1 answer:
bekas [8.4K]2 years ago
4 0

The coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

<h3>What is the coordinate of the point which divides a line segment in a specified ratio?</h3>

Suppose that there is a line segment \overline{AB}such that a point P(x,y) lying on that line segment \overline{AB} divides the line segment  \overline{AB} in m:n, then, the coordinates of the point P is given by:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)

where we have:

  • the coordinate of A is (x_1, y_1)
  • and the coordinate of B is (x_2, y_2)

We're given that:

  • Coordinate of A is (x_1, y_1) = (-7,2)
  • Coordinate of B is (x_2, y_2) = (9.-6)
  • The point P lies on AB such that AP:BP=3:1 (so m = 3, and n = 1)

Let the coordinate of P be (x,y), then we get the values of x and y as:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)\\\\(x,y) = \left( \dfrac{3(9) + 1(-7)}{3+1} , \dfrac{3(-6) + 1(2)}{3+1} \right)\\\\(x,y) = \left( \dfrac{20}{4} , \dfrac{-16}{4} \right) = (5,-4)

Thus, the coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

Learn more about a point dividing a line segment in a ratio here:

brainly.com/question/14186383

#SPJ1

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