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Paul [167]
2 years ago
13

Jesse and mark are jogging along the route shown at a rate of 12 miles per hour. they start by jogging south along capitol stree

t for 1 mile, then turn east on h street and jog for 1.75 miles. at that point, jesse is tired and decides to walk home along florida avenue at a rate of 5 miles per hour. mark plans to jog back the way they came. jesse wants to find out who will arrive home first and by how much time. which statements should he consider when solving the problem? check all that apply. a triangle. the sides are capitol street, h street, and they hypotenuse is florida avenue. jesse will walk home a distance of approximately 2.0 miles as found by evaluating 1 squared 1.75 squared = d squared and then 1 3.0625 = d squared. jesse will take about 0.4 hours to walk the rest of the way home as found by 2.0 = 5 (t). jesse will walk home a distance of approximately 2.25 miles as found by 1 squared 1.75 squared = d squared and then 2 3.0625 = d squared. mark will jog home a distance of 2.75 miles. it will take mark about 0.23 hours to jog home as found by 2.75 = 12 (t). mark will jog home a distance of 2.25 miles. mark will get home about 0.17 hours (or 10 minutes) sooner. mark will get home about 0.21 hours (or 12.5 minutes) sooner.
Mathematics
2 answers:
omeli [17]2 years ago
5 0

Answer:

I the person above is correct.

Step-by-step explanation:

kotykmax [81]2 years ago
4 0

Answer:

12457

Step-by-step explanation:

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Read 2 more answers
Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol
Dima020 [189]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

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Answer:

1056in^2

Step-by-step explanation:

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