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3 years ago

Show that 5(3y-2)=15y-10 for at least 5 values of y

1 answer:

7 0

<span>Solving the equation for Y = 1. 5 * (3 * 1 - 2) = 15 * 1 - 10 5 * (3 - 2) = 15 -10 5 * 1 = 5 5 = 5 Solving the equation for Y = 2. 5 * (3 * 2 - 2) = 15 * 2 - 10 5 * (6 - 2) = 30 -10 5 * 4 = 20 20 = 20 Solving the equation for Y = 4. 5 * (3 * 4 - 2) = 15 * 4 - 10 5 * (12 - 2) = 60 -10 5 * 10 = 50 50 = 50 Solving the equation for Y = 8. 5 * (3 * 8 - 2) = 15 * 8 - 10 5 * (24 - 2) = 120 -10 5 * 22 = 110 110 = 110 Solving the equation for Y = 9. 5 * (3 * 9 - 2) = 15 * 9 - 10 5 * (27 - 2) = 135 -10 5 * 25 = 125 125 = 125 This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9. However, it can be proved that the equation holds good for any value of y. Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided. So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>

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How can you determine the number of solutions for an equation

ryzh [129]

The way to determine the number of solutions is to complete the problem in multiple different ways.

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3 years ago

The product of two consecutive positive even integers is 440. what are the integers

Natali [406]

1st integer: x
2nd integer: x+2

Multiply them: x(x+2)=440
X^2+2x-440=0
Use the quadratic formula
x=-22 or x=20
Since x must be a positive integer number, x=20.

Answer:
1st: 20.
2nd: 22

Rate High and send a personal message if you want detailed answers on your math questions.

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3 years ago

Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was

frozen [14]

Answer: 101.69

Step-by-step explanation:

Formula we use to find the z-score :-

$z=\dfrac{x-\mu}{\sigma}$ (1)

Given : $\mu=90$

$\sigma=7$

Daniel's z score : z= 1.67

Let x be the raw score for Daniel's exam grade, then substitute the values of $\mu,\ \sigma\ and \ x$ in (1), we get

$1.67=\dfrac{x-90}{7}\\\\\Rightarrow\ x-90=7\times1.67\\\\\Rightarrow\ x=11.69+90=101.69$

Hence, the raw score for Daniel's exam grade = 101.69

3 0

3 years ago

Henry packed some apples in a box. The total mass of the box and the apples was 16 240 g. He packed some strawberries in a simil

icang [17]

Step-by-step explanation:

x = mass of apples

y = mass of strawberries

z = mass of the box

x = 3y

x + z = 16240

y + z = 6350

let's subtract the second from the first equation

x + z = 16240

- y + z = 6350

-----------------------

x - y + 0 = 9890

using the first identity in that result gives us

3y - y = 9890

2y = 9890

y = 4,945 g

x = 3y = 3×4945 = 14,835 g = the mass of the apples

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2 years ago

I only need 12 and 17, first good response i will give brainliest please i’m desperate

Mumz [18]

Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$